2D Shapes

Master perimeter and area of simple and composite shapes

CAPS Grade 10 Mathematics

This document provides an overview of the essential formulas and concepts related to 2D shapes. Learn to calculate perimeter and area of squares, rectangles, triangles, circles, and more.

Learning Outcomes

  • Calculate perimeter and area of squares, rectangles, triangles, and circles
  • Find perimeter and area of parallelograms, trapeziums, and rhombuses/kites
  • Identify and use perpendicular height correctly
  • Break down composite shapes into simpler components
  • Work backwards to find missing dimensions given area or perimeter
  • Apply unit consistency in all calculations

Shape Gallery

Core 2D Shape Formulas

ShapePerimeter FormulaArea Formula
SquareP = 4aA = a²
RectangleP = 2(l + w)A = l × w
TriangleP = a + b + cA = ½ × b × h
CircleC = 2πrA = πr²
ParallelogramP = 2(a + b)A = b × h
TrapeziumP = a + b + c + dA = ½ × (a + b) × h
Rhombus/KiteP = 4aA = ½ × d₁ × d₂

Quiz 1 - Shape Formulas

What is the area formula for a triangle

A) l × w
B) ½ × b × h
C) πr²
D) b × h

Key Concepts

1

Perpendicular Height

For triangles and parallelograms, always use the height that is perpendicular (90° angle) to the base. This is crucial for accurate area calculations.

2

Composite Shapes

Complex figures can often be broken down into simpler shapes like rectangles, triangles, or semi-circles for easier calculation.

3

Working Backwards

Sometimes you need to find a missing dimension (like radius or length) when the area or perimeter is provided. Rearrange formulas to solve for the unknown.

4

Unit Consistency

Ensure all dimensions are in the same unit (e.g., all in cm or all in m) before starting calculations.

Example Problems

Example 1: Area of a Rectangle

Problem

Length = 5 cm, Width = 3 cm. Find Area.

Solution
A = l × w = 5 cm × 3 cm = 15 cm²

Example 2: Perimeter of a Triangle

Problem

Sides = 3 cm, 4 cm, 5 cm. Find Perimeter.

Solution
P = a + b + c = 3 + 4 + 5 = 12 cm

Example 3: Area of a Composite Shape

Problem

Rectangle (6 cm × 4 cm) with semi-circle (diameter 4 cm). Find total area.

Solution
  1. Rectangle area: 6 × 4 = 24 cm²
  2. Semi-circle radius: r = 4/2 = 2 cm
  3. Semi-circle area: ½ × π × 2² = 2π cm² ≈ 6.28 cm²
  4. Total area: 24 + 6.28 = 30.28 cm²

Quiz 2 - Composite Shapes

A rectangle 8 cm × 3 cm has a triangle on top (base 8 cm, height 4 cm). Total area

A) 24 cm²
B) 32 cm²
C) 40 cm²
D) 48 cm²

Practical Applications

Architecture & Construction

Calculating area of land or perimeter of buildings for planning and resource allocation.

Gardening & Landscaping

Determining area of garden beds or perimeter of fences for material estimation.

Art & Design

Calculating canvas area or frame perimeter for proper fitting.

Practice & Assess

Test your knowledge with these interactive games.

Match - Shape to Formula

Square
A = a²
Rectangle
A = l × w
Circle
A = πr²
Triangle
A = ½ × b × h

Fill - Circle Area

Area of circle = π × ___²

Practice Questions

Q1

Square with side 6 cm. Find area and perimeter.

Q2

Rectangle length 8 cm, width 5 cm. Find area.

Q3

Triangle base 10 cm, height 6 cm. Find area.

Q4

Circle radius 7 cm. Find area (π ≈ 22/7).

Q5

Parallelogram base 12 cm, height 5 cm. Find area.

Q6

Trapezium parallel sides 6 cm and 10 cm, height 4 cm. Find area.

Summary of Key Concepts

Perpendicular Height: Always use height perpendicular to base
Composite Shapes: Break into simpler shapes
Working Backwards: Rearrange formulas to find missing dimensions
Unit Consistency: All measurements must be in same units

Key Terms

Perimeter Area Base Height Perpendicular Radius Diameter Composite Semi-circle Diagonal Parallelogram Trapezium Rhombus Kite
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